Building a Universal Binary from the Command line

The following topic applies to Xcode*.

Consider the following source file, HelloWorld.f90.

PROGRAM HelloWorld
    IMPLICIT NONE
#if defined( __i386__)
#define _PLATFORM_ "IA32"
#elif defined(__x86_64__)
#define _PLATFORM_ "Intel® 64"
#else
#define _PLATFORM_ "????"
#endif
    WRITE( *, * ) "Hello, ", _PLATFORM_, " World"
END PROGRAM HelloWorld

To build a universal binary executable from HelloWorld.f90:

Initialize the compiler environment by setting the environment variables. You can do this by executing compilervars.sh (or compilervars.csh) with the 'source' command:
source install-dir/bin/compilervars.sh<arg> where <arg> is ia32 or intel64.
Invoke the compiler with the m32 option and generate the object file, HelloWorld_32:
```
ifort -m32 -o HelloWorld_32 HelloWorld.f90
```
Invoke the compiler with the m64 option and generate the object file, HelloWorld_64:
```
ifort -m64 -o HelloWorld_64 HelloWorld.f90
```
Use the lipo utility to create the universal executable, HelloWorld, from the object files, HelloWorld_32 and HelloWorld_64:
```
lipo -create -arch i386 HelloWorld_32 -arch x86_64 HelloWorld_64 -output HelloWorld
```

To confirm that your process generates the correct result for both architectures, run the file utility on your universal binary:

file HelloWorld 
HelloWorld: Mach-O universal binary with 2 architectures 
HelloWorld (for architecture i386):Mach-O executable i386 
HelloWorld (for architecture x86_64): Mach-O 64-bit executable  x86_64

Note

The compiler defines the __x86_64__ macro on Intel® 64 architecture only. So, if you execute the universal binary, HelloWorld, on a system based on Intel® 64 architecture, the output is:

Hello, Intel® 64 World

On a system based on IA-32 architecture, the output is:

Hello, IA32 World

Building a Universal Binary from the Command line

Note

See Also